How do you find $f(x)+g(x), f(x)-g(x), f(x)*g(x), (f/g)(x)$ given $f(x)=3/(x-7)$ and $g(x)=x^2+5x$ ?

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Answer 1 · 2018-01-17T19:25:01

For $f(x) + g(x)$ , you just simply add the two functions. That is:

$f(x) + g(x) = 3/(x-7) + x^2 + 5x$ .

For $f(x) - g(x)$ , the same applies, but now we are subtracting the two functions; that is:

$f(x) - g(x) = 3/(x-7) - x^2 - 5x$ .

And we proceed like this to the other two cases:

$f(x).g(x) = (3/(x-7)) . (x^2 + 5x) = (3(x^2 + 5x))/(x-7)$ .

$f(x)/g(x)= (3/(x-7))/(x^2 + 5x) = (3)/((x-7)(x^2 + 5x))$ .

How do you find f(x)+g(x), f(x)-g(x), f(x)*g(x), (f/g)(x)f(x)+g(x), f(x)-g(x), f(x)*g(x), (f/g)(x) given f(x)=3/(x-7)f(x)=3/(x-7) and g(x)=x^2+5xg(x)=x^2+5x?