How do you find f'(x) using the definition of a derivative for #f(x)=sqrt(2x-1)#?

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Answer 1 · 2015-10-05T20:11:37

See the explanation.

#f'(x)=lim_(h->0) (f(x+h)-f(x))/h#

#f'(x)=lim_(h->0) (sqrt(2(x+h)-1)-sqrt(2x-1))/h=#

#=lim_(h->0) (sqrt(2(x+h)-1)-sqrt(2x-1))/h * (sqrt(2(x+h)+1)+sqrt(2x-1))/(sqrt(2(x+h)-1)+sqrt(2x-1))#

#=lim_(h->0) ((2(x+h)-1)-(2x-1))/(h(sqrt(2(x+h)-1)+sqrt(2x-1)))#

#=lim_(h->0) (2x+2h-1-2x+1)/(h(sqrt(2(x+h)-1)+sqrt(2x-1)))#

#=lim_(h->0) (2h)/(h(sqrt(2(x+h)-1)+sqrt(2x-1)))#

#=lim_(h->0) 2/(sqrt(2(x+h)-1)+sqrt(2x-1))#

#=lim_(h->0) 2/(2sqrt(2x-1))=1/sqrt(2x-1)#