How do you find five ordered pairs of #x+2y=8#?

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Answer 1 · 2016-08-08T19:07:42

#(6,1), (-4,6)# and so on .....
Infinitely many pairs can be found.

Change the equation around to have #y# as the subject.

#x + 2y = 8#

#2y = 8-x" " y = 4-x/2#

Now choose any value of #x#, (even numbers will be easier to work with), and calculate the corresponding value of #y#

If #x =6, y = 4-6/2 = 4-3 = 1" "rArr (6,1)#

If #x =-4, y = 4-(-4)/2 = 4+2 = 6" "rArr (-4,6)#

And so on ... choose #x#-values and find #y#-values.