How do you find #[fog](x)# and #[gof](x)# given #f(x)=1/2x-7# and #g(x)=x+6#?

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Answer 1 · 2017-03-07T06:49:06

The answers are #[fog] (x) =1/2x-4# and #[gof] (x)=1/2x-1#

This is a composition of functions

#f(x)=1/2x-7#

#g(x)=x+6#

#[fog] (x) =f(g(x))=f(x+6)=1/2(x+6)-7#

#=1/2x+3-7=1/2x-4#

#[gof] (x)=g(f(x))=g(1/2x-7)= 1/2x-7+6#

#=1/2x-1#