How do you find #(fog)(x)# given #f(x)=2x^3-5x^2# and #g(x)=2x-1#?
1 Answer
Apr 22, 2017
Explanation:
#"to evaluate" (f@g)(x)" substitute g(x) into f(x)"#
#f(color(red)(2x-1))#
#=2(color(red)(2x-1))^3-5(color(red)(2x-1))^2#
#"factor out " (2x-1)^2#
#rArr(2x-1)^2[2(2x-1)-5]#
#=(2x-1)^2(4x-7)#
#"which may be further expanded if you wish"#
