How do you find $(fog)(x)$ given $f(x)=x^2+3; g(x)=6x$ ?

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Answer 1 · 2017-02-28T16:36:31

$= 3(12x^2 + 1)$

Here, it is:

$(fog)(x) = f(g(x))$

$= f(6x)=(6x)^2+3 = 36x^2 + 3$

$= 3(12x^2 + 1)$

How do you find (fog)(x)(fog)(x) given f(x)=x^2+3; g(x)=6xf(x)=x^2+3; g(x)=6x?