# How do you find four consecutive integers whose sum is 366?

Sep 26, 2016

$90 , 91 , 92 , 93$

#### Explanation:

Let n be the first integer on the series:

$\therefore n + \left(n + 1\right) + \left(n + 2\right) + \left(n + 3\right) = 366$

$4 n + 6 = 366$

$4 n = 360$

$n = 90$

Thus the four consequtive integers are:

$90 , 91 , 92 , 93$