# How do you find g(1/3) given g(x)=x^2-x?

Dec 19, 2016

$- \frac{2}{9}$

#### Explanation:

$g \left(x\right) = {x}^{2} - x$

$g \left(\frac{1}{3}\right) \text{ }$means we replace all the $\text{xs" }$in the equation with$\text{ "1/3}$

$g \left(\frac{1}{3}\right) = {\left(\frac{1}{3}\right)}^{2} - \left(\frac{1}{3}\right)$

$g \left(x\right) = \frac{1}{9} - \frac{1}{3} = \frac{1}{9} - \frac{3}{9} = - \frac{2}{9}$