# How do you find general form of circle tangent to the y-axis and has a center of (-6, 7)?

##### 1 Answer

Dec 31, 2015

Use a little reasoning to find:

#(x+6)^2+(y-7)^2 = 6^2#

or if really fussy:

#(x-(-6))^2+(y-7)^2 = 6^2#

#### Explanation:

The general equation of a circle with centre

#(x-h)^2+(y-k)^2 = r^2#

In our case

graph{((x-(-6))^2+(y-7)^2-6^2)((x-(-6))^2+(y-7)^2-0.012)=0 [-24.75, 15.25, -3.52, 16.48]}