# How do you find h(10) given h(x)=-x^2-x?

Aug 18, 2016

$h \left(10\right) = 110$

#### Explanation:

$h \left(\textcolor{red}{x}\right) = - {\textcolor{red}{x}}^{2} - \textcolor{red}{x}$

$h \left(10\right)$ means that x = 10. So each x is replaced by 10

$h \left(\textcolor{red}{10}\right) = - {\textcolor{red}{10}}^{2} - \textcolor{red}{10}$

$h \left(\textcolor{red}{10}\right) = - 100 - 10 = - 110$

Remember that $y = f \left(x\right)$

$y = h \left(x\right)$

$y = h \left(10\right) = - 110$

means that for this function, when

$x = 10 , y = - 110$