How do you find $h(x)=f(x)+g(x)$ given $f(x)=3x-5$ and $g(x)=-x+2$ ?

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Answer 1 · 2017-01-17T23:37:37

$h(x) = 2x-3$

$h(x) = f(x)+g(x)$
$\ \ \ \ \ \ \ = (3x-5) + (-x+2)$
$\ \ \ \ \ \ \ = 3x-5 -x+2$
$\ \ \ \ \ \ \ = 2x-3$

Example:

$x=1 => f(1) = 3-5 \ \ \ \ = -2$
$x=1 => g(1) = -1+2 = 1$

Using:

$h(x) = f(x)+g(x) => h(1) = -2 + 1 =-1$
$h(x) = 2x-3 \ \ \ \ \ \ \ \ => h(1) = 2 -3 \ \ \ \ \=-1$

How do you find h(x)=f(x)+g(x)h(x)=f(x)+g(x) given f(x)=3x-5f(x)=3x-5 and g(x)=-x+2g(x)=-x+2?