How do you find k so that the line through (k,k+1) and (2,3) will have a slope of -1?

1 Answer
Sep 15, 2015

I could not find #k#!

Explanation:

Consider the general relationship that gives you the slope #m# as:
#m=(Deltay)/(Deltax)=(y_2-y_1)/(x_2-x_1)# (1)
Let us use our data:
#-1=(3-(k+1))/(2-k)# and solve for #k#:
#k-2=3-k-1#
#k+k=3+2-1#
#2k=4#
so #k=4/2=2#
BUT if you try this solution into your slope (equation 1) it doesn't work.
So I think it is not possible to have a line with this slope...