# How do you find #lim (sqrtx-1)/(x-1)# as #x->1^+# using l'Hospital's Rule or otherwise?

##### 1 Answer

Dec 9, 2016

I wouldn't use l'Hospital for this.

#### Explanation:

I would factor:

# = lim_(xrarr1) 1/(sqrtx+1) = 1/(1+1) = 1/2#

(Of course, I wouldn't write all that if I wasn't trying to explain.

**OR**

"Rationalize the numerator by multiplying by