# How do you find \lim _ { x \rightarrow 2} \frac { 2x + 5} { 11- x ^ { 3} }?

Jun 2, 2017

Answer: $3$

#### Explanation:

Evaluate ${\lim}_{x \to 2} \frac{2 x + 5}{11 - {x}^{3}}$

The first step in finding a limit is simply substituting the $x$ value and seeing if the denominator turns into $0$ (if the denominator becomes 0, then we would need to do some simplifying to make the denominator not be 0 when we substitute), so:
${\lim}_{x \to 2} \frac{2 x + 5}{11 - {x}^{3}} = \frac{2 \left(2\right) + 5}{11 - {\left(2\right)}^{3}}$

$= \frac{4 + 5}{11 - 8}$

$= \frac{9}{3}$

$= 3$, which is our answer.