How do you find #\lim _ { x \rightarrow 2} \frac { 2x + 5} { 11- x ^ { 3} }#?

1 Answer
Y
Jun 2, 2017

Answer: #3#

Explanation:

Evaluate #lim_(x->2)(2x+5)/(11-x^3)#

The first step in finding a limit is simply substituting the #x# value and seeing if the denominator turns into #0# (if the denominator becomes 0, then we would need to do some simplifying to make the denominator not be 0 when we substitute), so:
#lim_(x->2)(2x+5)/(11-x^3)=(2(2)+5)/(11-(2)^3)#

#=(4+5)/(11-8)#

#=9/3#

#=3#, which is our answer.

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