# How do you find parametric equations for the tangent line to the curve with the given parametric equations #x=7t^2-4# and #y=7t^2+4# and #z=6t+5# and (3,11,11)?

##### 1 Answer

Feb 22, 2015

The answer is:

The point

Now let's search the generic vector tangent to the curve:

So, for

So, remembering that given a point

so the tangent is:

N.B. The direction

that's simplier!