How do you find the equation of a line tangent to the curve at point #t=-1# given the parametric equations #x=t^3+2t# and #y=t^2+t+1#?
The answer is:
First of all let's find the cartesian coordinates of the point with
Than, let's find avector that is the direction of the tangent, putting
And finally, remembering that the equation of a line given a point
The solution is: