How do you find points of inflection and determine the intervals of concavity given #y=x^3-2x^2-2#?
1 Answer
The function is concave when
Explanation:
The function is
Calculate the first and second derivatives
The points of inflection are when
That is
The point of inflection is at
The intervals to consider are
Let's build a variation chart to determine the concavity
graph{x^3-2x^2-2 [-16.02, 16.01, -8.01, 8.01]}