How do you find real zero of a function f(x) = x^2 + 5x +6?

Apr 16, 2018

$x = - 3 , x = - 2$

Explanation:

$\text{equate "f(x)" to zero}$

$\Rightarrow {x}^{2} + 5 x + 6 = 0 \leftarrow \textcolor{b l u e}{\text{in standard form}}$

$\text{the factors of + 6 which sum to + 5 are + 3 and + 2}$

$\Rightarrow \left(x + 3\right) \left(x + 2\right) = 0$

$\text{equate each factor to zero and solve for x}$

$x + 3 = 0 \Rightarrow x = - 3$

$x + 2 = 0 \Rightarrow x = - 2$
graph{x^2+5x+6 [-10, 10, -5, 5]}