How do you find real zero of a function #f(x) = x^2 + 5x +6#?

1 Answer
Apr 16, 2018

Answer:

#x=-3,x=-2#

Explanation:

#"equate "f(x)" to zero"#

#rArrx^2+5x+6=0larrcolor(blue)"in standard form"#

#"the factors of + 6 which sum to + 5 are + 3 and + 2"#

#rArr(x+3)(x+2)=0#

#"equate each factor to zero and solve for x"#

#x+3=0rArrx=-3#

#x+2=0rArrx=-2#
graph{x^2+5x+6 [-10, 10, -5, 5]}