How do you find real zero of a function #f(x) = x^2 + 5x +6#?
1 Answer
Apr 16, 2018
Explanation:
#"equate "f(x)" to zero"#
#rArrx^2+5x+6=0larrcolor(blue)"in standard form"#
#"the factors of + 6 which sum to + 5 are + 3 and + 2"#
#rArr(x+3)(x+2)=0#
#"equate each factor to zero and solve for x"#
#x+3=0rArrx=-3#
#x+2=0rArrx=-2#
graph{x^2+5x+6 [-10, 10, -5, 5]}
