Question

How do you find real zero of a function `f(x) = x^2 - 8x + 12`?

Answer 1

Solve `f(x)=0` we want only real (not imaginary) solutions.

Explanation:

A real zero of a function is a real number that, when substituted for `x` makes `f(x)=0`

Solve `x^2-8x+12=0`

`x=2`, `x=6`

The (real) zeros are 2 and 6.