# How do you find real zero of a function f(x) = x^2 - 8x + 12?

Sep 11, 2015

Solve $f \left(x\right) = 0$ we want only real (not imaginary) solutions.

#### Explanation:

A real zero of a function is a real number that, when substituted for $x$ makes $f \left(x\right) = 0$

Solve ${x}^{2} - 8 x + 12 = 0$

$x = 2$, $x = 6$

The (real) zeros are 2 and 6.