# How do you find the 1st and 2nd derivative of 2e^(2x)?

Using $\frac{d}{\mathrm{dx}} {e}^{m x} = m {e}^{x}$
so $\frac{d}{\mathrm{dx}} 2 {e}^{2 x} = 2 \frac{d}{\mathrm{dx}} {e}^{2 x} = 2 \left(2 {e}^{2 x}\right) = 4 {e}^{2 x}$
And so, The ${d}^{2} / {\mathrm{dx}}^{2} 2 {e}^{2 x} = \frac{d}{\mathrm{dx}} 4 {e}^{2 x} = 4 \left(2 {e}^{2 x}\right) = 8 {e}^{2 x}$