Question

How do you find the 1st and 2nd derivative of `2e^(2x)`?

Answer 1

Using `d/dx e^(mx)=me^x`

Explanation:

so `d/dx 2e^(2x)=2d/dx e^(2x)=2(2e^(2x))=4e^(2x)`
And so, The `d^2/dx^2 2e^(2x)=d/dx 4e^(2x)=4(2e^(2x))=8e^(2x)`