How do you find the 6 trig functions of 120 degrees?

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Answer 1 · 2015-07-10T10:59:46

#sin120=sqrt(3)/2#

#cos120=-1/2#

#tan120=-sqrt(3)#

#ctg120=-sqrt(3)/3#

#sec120=-2#

#csec120=(2sqrt(3))/3#

To calculate #sin120# and #cos120# you can use the reduction formula, which says, that

#sin(180-x)=sinx# and #cos(180-x)=-cosx#

Rest of the functions can be calculated as:

#tanx=sinx/cosx#

#ctgx=1/tanx#

#secx=1/cosx#

#csecx=1/sinx#