Question

How do you find the 6 trigonometric functions for 10pi/3?

Answer 1

Find the 6 trig functions of `(10pi)/3.`

Explanation:

arc `(10pi)/3` --> arc `((4pi)/3 + 2pi)` --> `arc (4pi)/3`
On the trig unit circle,
`sin ((4pi)/3) = - sin pi/3 = - sqrt3/2`
`cos ((4pi)/3) = - cos pi/3 = - 1/2`
`tan ((4pi)/3) = sin/(cos) = sqrt3`
`cot ((4pi)/3) = 1/sqrt3 = sqrt3/3`
`sec ((4pi)/3) = - 2/sqrt3 = - 2sqrt3/3`