Question

How do you find the 6 trigonometric functions for 60 degrees?

Answer 1

`sin(60^@) = sqrt(3)/2color(white)("XX")csc(60^@) = 2/sqrt(3)`

`cos(60^@) = 1/2color(white)("XXXX")sec(60^@) = 2`

`tan(60^@) = sqrt(3)color(white)("XXX")cot(60^@)=1/sqrt(3)`

Explanation:

Use the basic trigonometric definitions and the diagram below.

Note: only the left half triangle is directly relevant; both sides combine to form an equilateral triangle from which (with the help of the Pythagorean Theorem) the required sides are derived.