How do you find the absolute value of $4 + 3 i$ $4+3i$ ?

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Answer 1 · 2017-02-04T11:16:27

5

$| 4 + 3 i | = \sqrt{4^{2} + 3^{2}} = \sqrt{(4 + 3 i) \cdot (4 - 3 i)} = 5$ $abs(4 + 3i) = sqrt(4^2 + 3^2 )= sqrt( (4 + 3 i) *(4 - 3i)) = 5$

How do you find the absolute value of 4+3i4+3i4+3i?