How do you find the absolute value of #4i#?

Question

8271 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-01T15:03:07

#|4i|=4#

Absolute value of a complex number #a+ib# is written as #|a+ib|# and is equal to #sqt(a^2+b^2)#.

Hence #|4i|#

= #|0+4i|#

= #sqrt(0^2+4^2)#

= #sqrt(0+16)#

= #sqrt16#

= #4#