How do you find the antiderivative of #e^(-2x^2)#?

1 Answer
Dec 3, 2016

Answer:

It doesn't have one, unless you allow the use of the error function #erf(x)# but that is a bit circular because the definition of #erf(x)# is #(2/sqrt(pi))int_-oo^x e^{-t^2}dt#.

Explanation:

A substitution like #x=t/sqrt(2)# looks like a good start.