# How do you find the antiderivative of (e^-2x)^2?

$\int {\left({e}^{-} 2 x\right)}^{2} \mathrm{dx} = \int {e}^{-} 4 {x}^{2} \mathrm{dx} = {e}^{-} 4 \int {x}^{2} \mathrm{dx} = {e}^{-} 4 \left({x}^{2 + 1} / \left(2 + 1\right)\right)$
$= \frac{{e}^{-} 4}{3} {x}^{3} + C , \mathmr{and} , {x}^{3} / \left(3 {e}^{4}\right) + C .$