How do you find the antiderivative of sin^2(x)cosx? Calculus Introduction to Integration Integrals of Trigonometric Functions 1 Answer Alexander Jul 10, 2016 int sin^2(x) cos(x) dx, let u = sin(x) -> du = cos(x) dx Thus int u^2 du = 1/3 u^3 + C = (sin^3(x))/3 + C Answer link Related questions How do I evaluate the indefinite integral intsin^3(x)*cos^2(x)dx ? How do I evaluate the indefinite integral intsin^6(x)*cos^3(x)dx ? How do I evaluate the indefinite integral intcos^5(x)dx ? How do I evaluate the indefinite integral intsin^2(2t)dt ? How do I evaluate the indefinite integral int(1+cos(x))^2dx ? How do I evaluate the indefinite integral intsec^2(x)*tan(x)dx ? How do I evaluate the indefinite integral intcot^5(x)*sin^4(x)dx ? How do I evaluate the indefinite integral inttan^2(x)dx ? How do I evaluate the indefinite integral int(tan^2(x)+tan^4(x))^2dx ? How do I evaluate the indefinite integral intx*sin(x)*tan(x)dx ? See all questions in Integrals of Trigonometric Functions Impact of this question 1541 views around the world You can reuse this answer Creative Commons License