# How do you find the asymptote for (-7x + 5) / (x^2 + 8x -20)?

Dec 13, 2016

You look for values of x for which there are no solutions possible, for example when the denominator is 0 that is a non-existent value. So -10 and 2 become asymptotes.

#### Explanation:

By setting

${x}^{2} + 8 x - 20 = 0$

you will find all the values for which this function will yield a non-existent value. You can use the quadratic formula to solve for x or you can factorise.

$\left(x 10\right) \cdot \left(x - 2\right)$