# How do you find the asymptotes for # (1-x)/(2x^2-5x-3)#?

##### 1 Answer

Apr 26, 2016

vertical asymptotes

horizontal asymptote y = 0

#### Explanation:

Vertical asymptotes occur as the denominator of a rational function tends to zero. To find the equation/s set the denominator equal to zero.

solve :

# 2x^2-5x-3 = 0 → (2x+1)(x-3) = 0 #

#rArr x = -1/2" and " x = 3" are the asymptotes "# Horizontal asymptotes occur as

# lim_(x to +- oo) , f(x) to 0# If the degree of the numerator < degree of the denominator,as is the case here then the equation is always

y = 0

graph{(1-x)/(2x^2-5x-3) [-10, 10, -5, 5]}