Question

How do you find the asymptotes for `f(x)= (2x)/(x^2+16)`?

Answer 1

Since the denominator will never equal zero, there are no vertical asymptotes .

Explanation:

There is one horizontal asymptote:

`""_(xrarr+-oo)^"lim"(2x)/(x^2+16)=0`

Horizontal : `y=0`

Hope that helped