# How do you find the asymptotes for f(x)= (2x)/(x^2+16)?

Jan 17, 2016

Since the denominator will never equal zero, there are no vertical asymptotes .

#### Explanation:

There is one horizontal asymptote:

$\text{_(xrarr+-oo)^"lim} \frac{2 x}{{x}^{2} + 16} = 0$

Horizontal : $y = 0$

Hope that helped