# How do you find the asymptotes for f(x)=(4x)/(x^2-8x+16)?

Jun 18, 2018

#### Answer:

HA= $y = 0$
VA= x= +/- 4
No slant asymptote

#### Explanation:

factored form of ${x}^{2} - 8 x + 16$ is $\left(x - 4\right) \left(x + 4\right)$ so therefor the VA are +/- 4
no slant asymptote because the degree of the numerator is not one more higher than the degree of the denominator.
Ha is 0 because the degree of x is higher on the bottom than the top.