# How do you find the asymptotes for #f(x) = (9x) / sqrt(16x^2 - 5)#?

##### 1 Answer

Jun 19, 2016

x=

y=±9/4

#### Explanation:

Vertical asymptotes would be given by

Thesy=

±

9

4

e would be x=

For horizontal asymptotes write f(x)= 9