# How do you find the asymptotes for #f(x)=(x^3+1)/(x^3+x)#?

##### 1 Answer

Mar 5, 2016

#### Answer:

Reformulate

#### Explanation:

#f(x) = (x^3+1)/(x^3+x) = (x^3+x+1-x)/(x^3+x) = 1+(1-x)/(x^3+x) = 1+(1-x)/(x(x^2+1))#

As

So there is a horizontal asymptote

When

Note that

graph{(x^3+1)/(x^3+x) [-10, 10, -5, 5]}