How do you find the asymptotes for #f(x)= (x)/(4x^2+7x+-2)#?

1 Answer
Apr 20, 2017

Answer:

#x_0=(-7-sqrt(17))/2#
OR
#x_0=(-7+sqrt(17))/2#
OR
#x_0=(-7-9)/2=-8#
OR
#x_0=(-7+9)/2=1#

Explanation:

Find, when there is #0# in denominator.
#b^2-4ac#
#49-32# OR #49+32#
#17# OR #81#
#x_0=(-7-sqrt(17))/2#
OR
#x_0=(-7+sqrt(17))/2#
OR
#x_0=(-7-9)/2=-8#
OR
#x_0=(-7+9)/2=1#