# How do you find the asymptotes for #g(x)= (x^3 -16x )/ (4x^2 - 4x)#?

##### 1 Answer

Aug 13, 2018

#### Answer:

**Vertical asymptote:** **slant asymptote :** **removable discontinuity:**

#### Explanation:

Vertical asymptote occur when denominator is zero.

The numerator's degree is greater (by a margin of 1), then we

have a slant asymptote which is found doing long division.

Therefore slant asymptote is

graph{(x^3-16x)/(4x^2-4x) [-40, 40, -20, 20]}[Ans]