# How do you find the asymptotes for #h(x)= (x^2-4)/(x)#?

##### 1 Answer

Jun 1, 2016

#### Answer:

oblique asymptote y = x

#### Explanation:

The first step is to divide out.

#rArr(x^2-4)/x=(x^2/x-4/x)=x-4/x# thus h(x) simplifies to

#h(x)=x-4/x# as

#xto+-oo,4/xto0" and " h(x)tox#

#rArry=x" is the only asymptote"#

graph{(x^2-4)/x [-10, 10, -5, 5]}