# How do you find the asymptotes for #h(x) = (x^3-8)/(x^2-5x+6)#?

##### 1 Answer

Feb 15, 2017

#### Answer:

Slant asymptote { #y=x+7.

Vertical asymptote : x = 3.

#### Explanation:

graph{((x^2+4x+4)/(x-3)-y)(y-x-7.9)(x-2+.01y)=0 [-45, 45, -20, 25]}

The graph is a hyperbola

Sans the hole at x = 2,

So,