# How do you find the asymptotes for #ln(x^2 + 1)#?

##### 1 Answer

May 15, 2016

#### Answer:

The function has no asymptotes.

#### Explanation:

The asymptote of the function

So, for

Attempting to solve

Thus, the graph of

graph{ln(x^2+1) [-31.48, 33.46, -11.76, 20.73]}