# How do you find the asymptotes for #(x^2+1)/(x^2-1)#?

##### 1 Answer

Nov 5, 2016

The vertical asymptotes are

The horizontal asymptote is

#### Explanation:

The denominator cannot be divided by

So the vertical asymptotes are

As the degree of the numerator and denominator are the same, we would not expect an oblique asymptote.

Limit

graph{(y-(x^2+1)/(x^2-1))(y-1)=0 [-7.9, 7.9, -3.95, 3.95]}