Question

How do you find the asymptotes for `(x^2+ 3x − 4) /( 4x^2 − 7x + 3)`?

Answer 1

`lim_(x->+-oo)y = 1/4`

`lim_(x->3/4) y= +-oo`

Explanation:

Write as:

`y=(cancel((x-1))(x+4))/(cancel((x-1))(4x-3))" "=" "(x+4)/(4x-3)`

`lim_(x->+-oo)y = 1/4`

`lim_(x->3/4) y= +-oo`