# How do you find the asymptotes for #(x^2-4x-32)/(x^2-16)#?

##### 1 Answer

Nov 20, 2015

Always **simplify first** before solving the problem ...

#### Explanation:

First, factor ...

Cancel out

[Note: The function is *undefined* at *removable discontinuity* .]

Now, the denominator is *zero* when **vertical asymptote** at

There is a **horizontal asymptote** at

hope that helped