How do you find the asymptotes for #((x-3)(9x+4))/(x^2-4)#?
Vertical asymptote x=2, x=-2
Equating denomnator =0 it is (x-2)(x+2)=0
The two vertical asymptotes are x=2 and x=-2. Next, dividing the numerator with denominator,
This gives y=9 as the horizontal asymptote.