# How do you find the asymptotes for ((x-3)(9x+4))/(x^2-4)?

Apr 18, 2016

Vertical asymptote x=2, x=-2
Horizontal y=9

#### Explanation:

Equating denomnator =0 it is (x-2)(x+2)=0

The two vertical asymptotes are x=2 and x=-2. Next, dividing the numerator with denominator,
f(x)=$\frac{9 {x}^{2} - 23 x - 12}{{x}^{2} - 4} = 9 + \frac{- 23 x + 24}{{x}^{2} - 4}$

This gives y=9 as the horizontal asymptote.