# How do you find the asymptotes for (x^3-x)/(x^3-4x)?

$\frac{x \left({x}^{2} - 1\right)}{x \left({x}^{2} - 4\right)} = \frac{{x}^{2} - 1}{{x}^{2} - 4}$
$\left({x}^{2} - {a}^{2}\right) = \left(x + a\right) \left(x - a\right)$