# How do you find the asymptotes for #(x-4)/(x^2-3x-4)#?

##### 1 Answer

Jan 16, 2016

#### Answer:

You start by factoring the denominator, which can be written as

#### Explanation:

Now the **vertical** discontinuities are clear, because that's when the denominator becomes zero:

If we near

So this is a 'repairable' discontinuity, while

We can now do the following:

The horizontal asymptote is when

Answer:

graph{(x-4)/(x^2-3x-4) [-10, 10, -5, 5]}