# How do you find the asymptotes for #x/sqrt(4x^2-1)#?

##### 1 Answer

Oct 21, 2016

#### Answer:

The vertical asymptotes are

And the horizontal asymptotes are

#### Explanation:

Let

To look for vertical asymptotes, we look at the denominator

and

we remove the

so the vertical asymptotes are

For horizontal asymptotes we find the limit

Rearrange

And the limit as

so horizontal asymptotes are

You can all this on the graph

graph{x/sqrt(4*x^2-1) [-2.5, 2.5, -1.25, 1.25]}