# How do you find the asymptotes for #y=(2x^2 + 3)/(x^2 - 6)#?

##### 1 Answer

Jan 2, 2016

**VA:**

**HA:**

#### Explanation:

**Vertical Asymptotes**

These will occur when the denominator equals

#x^2-6=0#

#x^2=6#

#x=+-sqrt6#

Thus, there are vertical asymptotes at

**Horizontal Asymptotes**

When the degree of the numerator and denominator are equal, like they are here, divide the terms with the greatest degree. In this case, those are

#(2x^2)/x^2=2#

There is a horizontal asymptote at

graph{(2x^2+3)/(x^2-6) [-19.62, 20.93, -8.83, 11.45]}