# How do you find the asymptotes for #y = (3-4x )/( 6x + sqrt(4x^2-3x-5))#?

##### 1 Answer

Dec 6, 2016

Horizontal:

#### Explanation:

To make y real,

Look at the dead ends

graph{y(6x+sqrt(4x^2-3x-5))+4x-3=0 [-5, 5, -2.5, 2.5]}