How do you find the asymptotes for #y=(3x+1)/(2-x)#?

1 Answer
Mar 7, 2016

Answer:

#VA: x=2#
#HA: y=-3#

Explanation:

To find vertical asymptote take the denominator and set it equal to 0 then solve for x.
To find the horizontal asymptote find the limits as x goes to infinity in both directions which means pick the highest degree term from the top and the bottom and divide them. Hence #y=lim x-> prop (3x)/-x# #y = -3#