# How do you find the asymptotes for #y = (3x^2+x-4) / (2x^2-5x) #?

##### 1 Answer

Nov 25, 2016

The vertical asymptotes are

No hole, No slant asymptote

The horizontal asymptote is

#### Explanation:

Let's factorise the denominator

The domain of

As you cannot divide by

Therefore, the vertical asymptotes are

As the degree of the numerator is

For the limits, we take the terms of highest degree

The horizontal asymptote is

graph{(y-((3x^2+x-4)/(2x^2-5x)))(y-3/2)=0 [-14.24, 14.24, -7.12, 7.12]}